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Bishesh Gautam asked a question

Dextrorotatory and dextrorotation are terms used in chemistry to describe the direction in which a substance rotates plane-polarized light. When a substance is said to be dextrorotatory, it means that it rotates plane-polarized light to the right or clockwise direction, whereas when it is levorotatory, it rotates plane-polarized light to the left or counterclockwise direction.

The terms "dextrorotatory" and "levorotatory" come from the Latin words "dexter" meaning "right" and "lævus" meaning...

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Gayatri Mishra asked a question

The foods we eat, the air we breathe, cleaning chemicals, our emotions and literally every object that we can see or touch, love, jealousy, infatuation and all share in chemistry. For all living things to function and survive, their bodies perform various chemical processes.



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Jessica Yadav asked a question

zinc will react with sulphuric acid forming zinc sulphate dissolved in solution and releasing hydrogen gas.
Zn + conc. 2 H2SO4 ZnSO4 + SO2 + 2 H2O

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Himal Rimal asked a question

Sigma bond is stronger than Pi bond because of the following reasons:

  1. The extent of overlapping in Sigma bond is greater than in Pi bond.
  2. The electron density in intermolecular axis is more in Sigma bond than in Pi bond.
  3. There is free rotation of atom about Sigma bond but not about Pi bond.
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Diwas Pandit asked a question

Yes, a vector which has zero magnitude is also a vector in case of two vectors travelling in opposite directions with equal magnitudes. At this case, the resultant vector has zero magnitude but it is still a vector. We call it a null vector.

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Nikas Ghimire asked a question


Program to input any number and display number of odd numbers in it;



#include<stdio.h>

#include<stdlib.h>

#include<conio.h>

#include<string.h>


int main() {

int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;

printf("Enter your number ==> ");

scanf("%d", &number);

num1 = number;

while(num1 != 0) {

rem = num1%10;

rem1 = rem%2;

if (rem1 != 0) {

num2 = num2*10 + rem;

}

num1 /= 10;

}

num3 = num2;

while (num2 != 0) {

...

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