Materials show varying behaviors based on their Poisson's ratio. High Poisson's ratio materials (near 0.5) contract significantly sideways when stretched and expand when compressed, seen in substances like rubber. Low Poisson's ratio materials (near 0) undergo minimal width change during axial deformation, typical of metals and common engineering materials.
Water is a vital substance for life on Earth, and it plays numerous important biological roles in living organisms. Some of the key biological roles of water are:
Universal solvent: Water is an excellent solvent for many substances, both organic and inorganic. This means that it can dissolve and transport a wide range of nutrients and minerals necessary for the growth and survival of living organisms.
Medium for metabolic reactions: Many metabolic reactions in living organisms require water...
conceptualizing the truth,in hegel's term. A lot of philosophers(like descartes' three kinds of ideas) in his time (and a lot of mindfulness practitioners these days)believed a higher form of truth(or knowledge) exists which cannot be articulated but is to be intuited and felt.Hegel didnt consider this to be scientific.you can never know if your intuition is true or its just you making the stuff up.
I think the best technique for memorizing is by assigning meaningfulness to things that are to be memorized.
Or in other words, relating things with a memorable story, simply, creating a story.
Do you remember yourself teaching us to memorize things easily. We had related words to a story and almost everyone in the class remembered at least 25 words among the total of 30. I still remember "Bhachyeko Haat". Haha!
Memory export Jim Kwik says that anything combined with emotion becomes a...
Program to input any number and display number of odd numbers in it;
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
int main() {
int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;
printf("Enter your number ==> ");
scanf("%d", &number);
num1 = number;
while(num1 != 0) {
rem = num1%10;
rem1 = rem%2;
if (rem1 != 0) {
num2 = num2*10 + rem;
}
num1 /= 10;
}
num3 = num2;
while (num2 != 0) {
...
