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Mattrab Community - SXC asked a question

Log2aa=x    then, a=(2a) ......(1)

Log3a2a=y    then,2a=(3a)y ......(2)

Log4a 3a=z  then, 3a=(4a)z ......(3)

So, 

a=(2a)x  [from (1)]

Or, a=(3a)xy    [from(2)]

Or, a=(4a)xyz     [from(3)]

Multiplying both sides by 4a,

4a.a=4a.(4a)xyz  

Or,(2a)² =(4a)xyz + 1 

Or,(3a)2y =(4a)xyz+1 

Or,(4a)2yz =(4a)xyz+1 

Or, 2yz = xyz+1 .proved.



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Bishesh Gautam asked a question

Dextrorotatory and dextrorotation are terms used in chemistry to describe the direction in which a substance rotates plane-polarized light. When a substance is said to be dextrorotatory, it means that it rotates plane-polarized light to the right or clockwise direction, whereas when it is levorotatory, it rotates plane-polarized light to the left or counterclockwise direction.

The terms "dextrorotatory" and "levorotatory" come from the Latin words "dexter" meaning "right" and "lævus" meaning...

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Diwas Pandit asked a question

Yes, a vector which has zero magnitude is also a vector in case of two vectors travelling in opposite directions with equal magnitudes. At this case, the resultant vector has zero magnitude but it is still a vector. We call it a null vector.

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Nikas Ghimire asked a question


Program to input any number and display number of odd numbers in it;



#include<stdio.h>

#include<stdlib.h>

#include<conio.h>

#include<string.h>


int main() {

int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;

printf("Enter your number ==> ");

scanf("%d", &number);

num1 = number;

while(num1 != 0) {

rem = num1%10;

rem1 = rem%2;

if (rem1 != 0) {

num2 = num2*10 + rem;

}

num1 /= 10;

}

num3 = num2;

while (num2 != 0) {

...

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2 Answers

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