or
Bishesh Gautam asked a question

Here, the given equation of parabola is y2= 8x.

The equation of tangent to the parabola y2=8x is,

y= mx + 2/m

This tangent passes through the point (-2, 3)

So, 3 = -2m + 2/m

or, 3m + 2m2 = 2

or, 2m2+3m - 2= 0

or, 2m2 + (4 - 1)m -2 = 0

or, 2m2 + 4m - m - 2 = 0

or, 2m(m + 2) - 1(m+2) = 0

or, (m + 2) (2m - 1) = 0

Either, Or,

m = -2 m = 1/2

Required angle is,




0 Thanks
2 Answers

Mattrab Community

Create, share and learn from the unlimited notes, photos and videos and ask your questions, answer your friends all over Nepal and grow. Create, share and learn.

Ask Mattrab is changing soon

We are excited for you to try new features. What are you excited about?

Close Open App