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Arya Jha • asked a question

Using bisection method, find the root of the equation f(x)=x² -6logx-3=0(2<=x<=3)'correct to 4 decimal places with an accuracy of 10^-2 .

Here, f(x)=x² -6 logx-3=0

f(2)=4-6 log2-3=-0.806

f(3)=9-6 log3-3=3.1373

f(2).f(3)=-0.806*3.1373=-2.529422 which is negative.

Hence, the root lies between 2 and 3

c₀ =(2+3)/2=2.5

f(2.5)=6.25-6 log 2.5-3=0.8623

Now

n	a(-ve)	b(+ve)	c_n	f(c_n)
0	2	3	2.5	0.8623
1	2	2.5	2.25	-0.050595
2	2.25	2.5	2.375	0.38664
3	2.25	2.375	2.3125	0.1631658
4	2.25	2.3125	2.28125	0.05506
5	2.25	2.28125	2.265625	0.001925

From the table,

f(2.265625)=0.001928<10^-2

Therefore, the...

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Abhishek Yadav • asked a question

Evaluate the integral:

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Ashok Shah • about 1 year ago

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