Hello Subash!
Here is the solution for the question you are asking for, I solved it in procedural way but if you are among the one who prefer OOP style then you can still ask it for me cause I have solved it from both methods but here I am just going to leave procedural one....
//author:Manish Acharya
import java.util.Scanner;
import java.util.*;
public class idgenerator {
public static void main(String[] args) {
String small_name="", long_name="", new_small_name="", new_long_name="";
char lr='a',...
Program to input any number and display number of odd numbers in it;
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
int main() {
int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;
printf("Enter your number ==> ");
scanf("%d", &number);
num1 = number;
while(num1 != 0) {
rem = num1%10;
rem1 = rem%2;
if (rem1 != 0) {
num2 = num2*10 + rem;
}
num1 /= 10;
}
num3 = num2;
while (num2 != 0) {
...
Sunlight reaches Earth's atmosphere and is scattered in all directions by all the gases and particles in the air. Blue light is scattered more than the other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time.
Materials show varying behaviors based on their Poisson's ratio. High Poisson's ratio materials (near 0.5) contract significantly sideways when stretched and expand when compressed, seen in substances like rubber. Low Poisson's ratio materials (near 0) undergo minimal width change during axial deformation, typical of metals and common engineering materials.
The Wheatstone bridge is not suitable for measuring very low resistance because it is based on a ratio of two resistances, and the resolution of the bridge decreases as the ratio approaches 1. This means that the Wheatstone bridge is not accurate enough to measure very small changes in resistance.