or
Mattrab Community - SXC asked a question

Log2aa=x    then, a=(2a) ......(1)

Log3a2a=y    then,2a=(3a)y ......(2)

Log4a 3a=z  then, 3a=(4a)z ......(3)

So, 

a=(2a)x  [from (1)]

Or, a=(3a)xy    [from(2)]

Or, a=(4a)xyz     [from(3)]

Multiplying both sides by 4a,

4a.a=4a.(4a)xyz  

Or,(2a)² =(4a)xyz + 1 

Or,(3a)2y =(4a)xyz+1 

Or,(4a)2yz =(4a)xyz+1 

Or, 2yz = xyz+1 .proved.



9 Thanks
2 Answers
Bijaya Rajbhandari asked a question

Not even a single member ofAksionov'sfamily was concerned about his well-being when he was at his lowest.Along with the judges of the court even his wife did not trust him.Hewas imprisoned for the crime he did not commit.With time he learnt to forgive people, but he did not forget their mistreatment.

2 Thanks
3 Answers
Rabin Kalikote over 3 years ago
13 Claps
2 Comments
Bal Bahadur BK

Great my son!

Reply over 3y
Pranish Uprety

You've been truly inspiration, dai! Congratulations to you and all of us.

Reply over 3y

Mattrab Community

Create, share and learn from the unlimited notes, photos and videos and ask your questions, answer your friends all over Nepal and grow. Create, share and learn.

Ask Mattrab is changing soon

We are excited for you to try new features. What are you excited about?

Close Open App