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Here, f: A—>B

f(x)= (x-1)/(x+2)  ;  x   -2 

A= {-1,0,1,2,3,4}

B= {-2,1,-1/2,0,1/2,1/4,2/5}

Range = {-2,-1/2,0,1/4,1/2,2/5}

As range is not equal to codomain so the given function is not bijective. 

We can make it bijective by omitting {1} from set B 

तपाईंको जीवनमा सामाजिक अधययनले के कसता सकारातमक परभाव परेका छन , बुँदागत रुपमा  लेखनुहोस I

सामाजिक अधययनले मेरो जीवनका पारेका सकारातमक अधययन निमनाअनुसार बुँदागत  रुपमा परसतुत गरेको छु :

1. मैले संविधान वयवसथा गरेको हक, अधिकार, करतवय, दायितव आदि बारे बुझन पाएको छु I

2. मैले करतवयपरायणताको भाव बोध गरेको छु I

3. समाजका रीतिरिवाज, संसकार, परमपरा आदिको अधययनबाट फरक परिवेशमा समेत समावेशन हुन सकने    सिपको विकास गरेको छु I 

4. राषटरिय समपदाको संरकषण र देशको पृषठभूमिपरति पुरखाले...

#include<stdio.h>

#include<conio.h>

#include<string.h>

int main() {

int i, number, num1, num2=0;

char str1[50];

num1 = number;

for(i=2; i<=20; i+=2) {

printf("%d", i);

printf(", ");

}

return 0;

}

In benzene molecule, carbon and carbon bond can't have polarity because there is not any electronegativity difference and the carbon hydrogen is also not much polar because the electronegativity difference is almost zero and also the small pull due to small difference in Electronegativity is balanced due to even pull from all directions.

In chlorobenzene the electronegativity difference between carbon and chlorine is very high so, it is polar.

(to compare polarity first check electronegativity...