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#include<stdio.h>
#include<conio.h>
#include<string.h>
int main() {
int i, number, num1, num2=0;
char str1[50];
num1 = number;
for(i=2; i<=20; i+=2) {
printf("%d", i);
printf(", ");
}
return 0;
}
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Here, the given equation of parabola is y2= 8x.
The equation of tangent to the parabola y2=8x is,
y= mx + 2/m
This tangent passes through the point (-2, 3)
So, 3 = -2m + 2/m
or, 3m + 2m2 = 2
or, 2m2+3m - 2= 0
or, 2m2 + (4 - 1)m -2 = 0
or, 2m2 + 4m - m - 2 = 0
or, 2m(m + 2) - 1(m+2) = 0
or, (m + 2) (2m - 1) = 0
Either, Or,
m = -2 m = 1/2
Required angle is,
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