or
Nikas Ghimire asked a question


#include<stdio.h>

#include<conio.h>

#include<string.h>


int main() {

int i, nextTerm;

int t1 = 2, t2 = 2;

nextTerm = t1+t2;


printf("%d, %d, ", t1, t2);

for (i = 3; i <= 10; ++i) {

printf("%d, ", nextTerm);

t1 = t2;

t2 = nextTerm;

nextTerm = t1 + t2;

}


return 0;

}


2 Thanks
2 Answers
Raunak Kumar asked a question

BODMAS=Bracket, Order, Division, Multiplication, Addition and Subtraction. In certain regions, PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition and Subtraction) is the synonym of BODMAS. It explains the order of operations to solve an expression.

10 Thanks
2 Answers
Bikash T. Magar asked a question

Balance on a bicycle is a matter of constantly correcting against falls, and it's easier when the speed is higher because the inertia of moving forward overcomes the need for corrective actions.

5 Thanks
2 Answers
Sanam asked a question

First learn basic HTML, then CSS and responsive CSS for Static websites and thereafter JavaScript and PHP for dynamic pages. If you also want to learn jQuery for more better works learn it at the same time with JavaScript

3 Thanks
2 Answers
Nikas Ghimire asked a question


Program to input any number and display number of odd numbers in it;



#include<stdio.h>

#include<stdlib.h>

#include<conio.h>

#include<string.h>


int main() {

int i, number, num1, num2=0, num3, num4 =0, rem, rem1, rem2, rev = 0;

printf("Enter your number ==> ");

scanf("%d", &number);

num1 = number;

while(num1 != 0) {

rem = num1%10;

rem1 = rem%2;

if (rem1 != 0) {

num2 = num2*10 + rem;

}

num1 /= 10;

}

num3 = num2;

while (num2 != 0) {

...

0 Thanks
2 Answers

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