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Rabin Kalikote over 3 years ago
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Bal Bahadur BK

Great my son!

Reply over 3y
Pranish Uprety

You've been truly inspiration, dai! Congratulations to you and all of us.

Reply over 3y
grishma gautam asked a question

1.ans:  No the tension in the string of a simple pendulum is not constant throughout the motion                                     

v is velocity of the bob and theta is the angle made by the string with vertical axis.
as v and  both are variable T is also variable.
T is maximum at mean position as at mean position v is max and the angle is minimum.


2.ans: If the amplitude of the simple...

1 Thanks
2 Answers
Shibu oli asked a question

In mitosis, the prophase is further understood by dividing it into the given sub-stages:

1.Leptotene :

In this stage the nucleus enlarges in size in the chromosome. The chromosomes appear thin, thread-like and single-stranded in this stage. They have swollen or beaded structures along their length and their ends appear converged towards one side of the nucleus called bouquet.

2.Zygotene:

In this stage, the identical chromosomes come together and form bivalent or homologous pairs. Further, ...

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2 Answers
UJJWAL JHA over 2 years ago
1 Clap
1 Comments
KRISH YADAV

Materials show varying behaviors based on their Poisson's ratio. High Poisson's ratio materials (near 0.5) contract significantly sideways when stretched and expand when compressed, seen in substances like rubber. Low Poisson's ratio materials (near 0) undergo minimal width change during axial deformation, typical of metals and common engineering materials.

♪⚝Sanjiv❀Jaiswal❁⩸ asked a question


Compounds with hydrogen bonding tend to have higher melting and boiling points because the hydrogen bonding leads to stronger intermolecular forces. Intermolecular forces are the attractive forces between molecules, and they affect the physical properties of a substance, including melting and boiling points.

Hydrogen bonding is a particularly strong type of intermolecular force that occurs when a hydrogen atom is bonded to a highly electronegative atom such as nitrogen, oxygen, or fluorine....

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Arya Jha asked a question

Here, f(x)=x2 -6 logx-3=0

f(2)=4-6 log2-3=-0.806

f(3)=9-6 log3-3=3.1373

f(2).f(3)=-0.806*3.1373=-2.529422 which is negative.

Hence, the root lies between 2 and 3

c0 =(2+3)/2=2.5

f(2.5)=6.25-6 log 2.5-3=0.8623

Now

n
a(-ve)
b(+ve)
cn
f(cn)
0
2
3
2.5
0.8623
1
2
2.5
2.25
-0.050595
2
2.25
2.5
2.375
0.38664
3
2.25
2.375
2.3125
0.1631658
4
2.25
2.3125
2.28125
0.05506
5
2.25
2.28125
2.265625
0.001925

From the table,

f(2.265625)=0.001928<10-2

Therefore, the...

0 Thanks
2 Answers

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