Here, f(x)=x2 -6 logx-3=0
f(2)=4-6 log2-3=-0.806
f(3)=9-6 log3-3=3.1373
f(2).f(3)=-0.806*3.1373=-2.529422 which is negative.
Hence, the root lies between 2 and 3
c0 =(2+3)/2=2.5
f(2.5)=6.25-6 log 2.5-3=0.8623
Now
| n | a(-ve) | b(+ve) | cn | f(cn) |
| 0 | 2 | 3 | 2.5 | 0.8623 |
| 1 | 2 | 2.5 | 2.25 | -0.050595 |
| 2 | 2.25 | 2.5 | 2.375 | 0.38664 |
| 3 | 2.25 | 2.375 | 2.3125 | 0.1631658 |
| 4 | 2.25 | 2.3125 | 2.28125 | 0.05506 |
| 5 | 2.25 | 2.28125 | 2.265625 | 0.001925 |
From the table,
f(2.265625)=0.001928<10-2
Therefore, the...
तपाईंको जीवनमा सामाजिक अधययनले के कसता सकारातमक परभाव परेका छन , बुँदागत रुपमा लेखनुहोस I
सामाजिक अधययनले मेरो जीवनका पारेका सकारातमक अधययन निमनाअनुसार बुँदागत रुपमा परसतुत गरेको छु :
1. मैले संविधान वयवसथा गरेको हक, अधिकार, करतवय, दायितव आदि बारे बुझन पाएको छु I
2. मैले करतवयपरायणताको भाव बोध गरेको छु I
3. समाजका रीतिरिवाज, संसकार, परमपरा आदिको अधययनबाट फरक परिवेशमा समेत समावेशन हुन सकने सिपको विकास गरेको छु I
4. राषटरिय समपदाको संरकषण र देशको पृषठभूमिपरति पुरखाले...
Here, f: A—>B
f(x)= (x-1)/(x+2) ; x -2
A= {-1,0,1,2,3,4}
B= {-2,1,-1/2,0,1/2,1/4,2/5}
Range = {-2,-1/2,0,1/4,1/2,2/5}
As range is not equal to codomain so the given function is not bijective.
We can make it bijective by omitting {1} from set B
Makar disclosed that he had killed the merchant because he realized his mistake and Aksionov's suffering and now he wanted to make Aksionov release from the prison.
Where could be the end? Any thoughts?
The end is when node_modules finishes installing.